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Electrical Exam Preparations Preparing and studying for your upcoming electrical examinaton ? Where here to help !

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  #1   IP: 124.82.118.83
Old June 5th, 2009, 11:34 PM
alternativess alternativess is offline
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Question What's the way use to factor this?

I was stucked on studying this math on factoring problem.

What's the ways use to factor the equation on the left side, so that it becomes the equation on the right side.



Appreciate for any math experts' guide. Thanks
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  #2   IP: 207.35.6.2
Old June 8th, 2009, 06:06 AM
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Too broad a queston. Give us the equation.
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  #3   IP: 75.110.95.224
Old June 8th, 2009, 06:21 PM
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Tear the equation right where the = sign is and put the left piece on the right.
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  #4   IP: 76.202.6.94
Old June 19th, 2009, 08:01 PM
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Yep....turn the page over!
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  #5   IP: 71.126.189.137
Old October 6th, 2009, 04:19 PM
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I'll give you some hints.

1. Multiply through the right side of the equation.
n(a - b)(c - d) = nac - nad - nbc +nbd

2. Use a calculator and figure out what happens if you multiply a number raised to a positive power by the same number raised to the same (but negative) power.

3. Combine like terms from both sides of the equation.

4. Look up the equivalent way to express a term with a negative power, as one with a positive power.

5. Solve using the quadratic equation.

I just ran through the numbers. Lets just say that you won't need to do steps 4 and 5.

Last edited by CR500 : October 6th, 2009 at 04:36 PM.
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  #6   IP: 130.127.63.136
Old October 7th, 2009, 07:52 AM
househelper househelper is offline
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Quote:
Originally Posted by CR500 View Post
I'll give you some hints.

1. Multiply through the right side of the equation.
n(a - b)(c - d) = nac - nad - nbc +nbd

2. Use a calculator and figure out what happens if you multiply a number raised to a positive power by the same number raised to the same (but negative) power.

3. Combine like terms from both sides of the equation.

4. Look up the equivalent way to express a term with a negative power, as one with a positive power.

5. Solve using the quadratic equation.

I just ran through the numbers. Lets just say that you won't need to do steps 4 and 5.
That's the easy part... but how do you come up with the 1.5856 and .1577 numbers?
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